Solve the equation \(5(2c - 3 ... This means \(3r + 2\) will all be multiplied by 7. To show this in algebra, use a bracket for \(3r + 2\) to show that both terms are being multiplied by ...

\(\mathbf{ax^2 + bx + c = 0}\) where \(a\), \(b\) and \(c\) are numbers. Both \(b\) and/or \(c\) can be equal to zero. In this section, solving equations where \(a >1 ...